CONSTRUCTA Fridge Uživatelský manuál Strana 4

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4
How to improve the efficiency
of a heat engine.
Increase T
h
This requires high temperature materials
Decrease T
c
This requires efficient heat transfer.
.
Cogeneration
Use of waste heat
This power plant in Denmark uses the waste heat to heat green
houses nearby.
Refrigerators
Coefficient of performance
COP- the heat removed from the
cold source divided by the work
done.
cc
hc
QQ
COP
wQQ
==
c
hc
T
COP
TT
=
The maximum Carnot COP
since
c
h
hc
Q
Q
TT
=
Refrigerator
1 Compressor – gas is compresses and heated
2 Heat exchange coils - the heat is released
from the gas and exhausted outside of the
refrigerator.
3 Expansion valve – The pressure is decreased
after going through the valve. The gas is cooled
4 Cooling coils- Heat is absorbed from within the
refrigerator. The gas is heated.
The refrigerator uses a liquid with a low
boiling point. The evaporation takes up heat
from the refrigerator and the condensation of
the gas releases the heat outside the refrigerator.
1
2
3
4
Refrigerator
A freezer is kept at a temperature of 0
o
F. What is the maximum
COP for a Carnot refrigerator with output temperature of 85
o
F. If the
electrical energy use is 500kWh/year how much heat is removed in
one year, assume 90% conversion of electrical energy to work.
T
c
= ( 0 -32)(5/9) +273=255 K
T
h
=(85-32)(5/9)+273=302 K
c
hc
T
COP
TT
=
255
302
54
255
.==
3
60min 60
0.9(500 10 )
min
s
WxWhr
hr
⎛⎞
=⋅
⎜⎟
⎝⎠
9
1.62 10= xJ
c
Q
COP
w
=
(
)
9 9
5.4 1.62 10 8.7 10== =
c
xQCOPw x x J
Heat removed
COP
Work
Heat
Summary
The second law of thermodynamics limits the efficiency
of heat engines to less than 100%
The Carnot cycle is a reversible cycle taking in heat at
high T and exhausting heat at low T.
The maximum efficiency of a heat engine working
between two temperatures is the Carnot efficiency that
depends only on the ratio of the absolute temperatures.
Refrigerators and heat pumps are heat engines run in
reverse.
The maximum coefficient of performance is determined
by a Carnot cycle.
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